Question

The binding energy per nucleon of deuteron (1H^2) and helium nucleus (2He^4) is 1.1 MeV and 7 MeV respectively.

Answer 1

Answer : 23.6MeV
If two deuteron nuclei react to form a single helium nucleus ,
2
1
H+
2
1
H→
4
2
H+Q. We need to calculate Q.
Energy released = total binding energy of product - total binding energy of reactants

Answer 2

Answer:

23.6

Explanation:

Total binding energy of Helium = 4*7 = 28

Total binding energy of Deuteron = 2*1.1 = 2.2

Since there are two Deuteron = 2*2.2 = 4.4

Now, required total energy = 28 - 4.4 = 23.6