Math, asked by farjadboy, 1 year ago

the bisect of angles L and M meet in 0. Prove that ON bisects angle LMN

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Answered by swatisharma28589

Construction: Join AM Proof: ∵ A lies on bisector of ∠N ∴ A is equidistant from MN and LN. Again, A lies on bisector of ∠L ∴ A is equidistant from LN and LM. Hence, A is equidistant from all sides of the triangle LMN. ∴ A lies on the bisector of ∠MRead more on Sarthaks.com - https://www.sarthaks.com/155803/triangle-lmn-bisectors-of-interior-angles-at-and-intersect-each-other-at-point-prove-that

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