Question

The bisector AD of angle A meets BC at D. Find the coordinates of D.
9. The vertices of a triangle ABC are A(3,2,0), B(5, 3, 2) and (-9,6,-3). ​

Answer 1

Answer:

-12, 4,-3 shayad answer ho skta h. i am not sure

Step-by-step explanation:

ho skta h aapko yeh answer aa jaye

Answer 2

Answer:

In ΔABC,

AD is the bisector of

∠AΔ meets BC at D.

∴

DC

BD

=

AC

AB

or

AB=

(5−3)

2

+(3−2)

2

+(2−0)

2

=

2

2

+1

2

+2

2

=

9

=3

AC=

(−9−3)

2

+(6−2)

2

+(−3−0)

2

=

12

2

+4

2

+3

2

=

144+16+9

=13

DC

BD

=

13

3

Coordinate of D ⇒

[

3+13

3(−9)+13(5)

,

3+13

3(6)+13(3)

,

3+13

3(−3)+13(2)

]

=(

8

19

,

16

57

,

16

17)