The bisector of angle A and angle B meet at point R.if angle C =110 degree and angle D = 50 degree. find the measure of angle ARB
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Answer:
∠ARB = 80°
Step-by-step explanation:
Supposing that ABCD is a quadrilateral.
A+B+C+D = 360 [angle sum property in quadrilateral]
Let the measure of angle A be = 2x
Let the measure of angle A be = 2y
∴ 2x+2y+110+50 = 360
2x+2y = 200
x+y = 100
In ΔARB sum of two angles is 100°
∴∠ARB = 180 - 100 = 80°
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