The bisector of angleA and angleB meet at a point P. If angle C = 50° and angle D = 100%, find the measure of angle APB
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the answer for this question is 75
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in a quadrilateral opp side sum - 180°
so angle bcd+angle bad =180°
180-50=130°
2x=130°
x=65°
so Angle adc + angle abc = 180°
180-100=80°
2y=80
y=40°
in triangle APB
Angle pab + angle pba + angle APB = 180°
65°+40°+ APB = 180°
180° - 105°= APB
APB=75°
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