Question

the bisector of base angle of a triangle enclose a right angle in any case​

Answer 1

Answer:

and C respectively.

Now, in △ABC,

∠A+∠B+∠C=180°

∠B+∠C=180°−∠A.....(1)

Now, in △BOC,

∠BOC+

2

1

∠B+

2

1

∠C=180°

∠BOC+

2

1

(∠B+∠C)=180°

∠BOC+

2

1

(180°−∠A)=180°

⇒∠BOC=180°−90°+

2

1

∠A

⇒∠BOC=90°+

2

1

∠A

⇒∠BOC>90°

Thus it is proved that the bisector of base angles of a triangle cannot enclose a right