The bisector of P in PQR intersects QR in D.
If QD: RD = 4:7 and PR=14. Then PQ=
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In △PQR, the bisector of ∠P intersects
QR
in D.
Given QD:RD=4:7, PR=14
We know that,
PR
PQ
=
RD
QD
⟹
14
PQ
=
7
4
⟹PQ=
7
4×14
=8
Hence, the answer is 8.
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