The bisector of the angle A of a triangle ABC meets BC in D and BC is produced upto E. Prove that ∠ABC + ∠ACE = 2∠ADC .
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Step-by-step explanation:
angleABC+angleBAD=angleADC angleABD+angleBAC=angleACE
angleABD+2angleBAD=angleACE angleABC +2angleADC-2angleABD=angleACE
2angleADC=angleABC+angleACE
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