the bisector of the base angles Q and R of an equitateral triangle PQR meet at S . ST and SM are drawn parallel to sides PQ and PR.. then show that QT=TM=MR..
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An angle bisector of an angle of a triangle divides the opposite side in two segments that are proportional to the other two sides of the triangle. Proof: Draw ↔BE∥↔AD . Extend ¯CA to meet ↔BE at point E .
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