The bisector of the vertical ∠ A of an isosceles triangle ABC meets the base BC at D. If AB = AC = 5 cm, AD = 3cm, Find the length of BC.
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in tri ABD
AB^2= AD^2+BD^2
25-9=BD^2
BD=4cm
andIN TRI ADC
AC^2=AD^2+CD^2
25-9=DC^2
DC=4cm
BC=BD+DC
BC=8cm
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