Question

The bisectors of angle B and angle C of quadrilateral ABCD meet at a point R inside the quadrilateral. If angle A=95° and angle B=111°, Find angle BRC.​

Answer 1

Answer:

Step-by-step explanation:

quadrilateral ABCD,

A!=95

0

,D!=111

0

A!+D!=111+95=206

0

B!+C!=360

0

−206

0

=154

0

In ΔBRC,

(BRC)!+(RBC)!+(BCR)!=180

0

(BRC)!+

2

1

​

(B!+C!)=180

0

(BRC)!+

2

1

​

(154)=180

0

(BRC)!=180

0

−77

0

=103

0

∴(BRC)!=103