The bisectors of angle B and angle C of quadrilateral ABCD meet at a point R inside the quadrilateral. If angle A=95° and angle B=111°, Find angle BRC.
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Answer:
Step-by-step explanation:
quadrilateral ABCD,
A!=95
0
,D!=111
0
A!+D!=111+95=206
0
B!+C!=360
0
−206
0
=154
0
In ΔBRC,
(BRC)!+(RBC)!+(BCR)!=180
0
(BRC)!+
2
1
(B!+C!)=180
0
(BRC)!+
2
1
(154)=180
0
(BRC)!=180
0
−77
0
=103
0
∴(BRC)!=103
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