the bisectors of angle P and angle Q of a quadrilateral PQRS meet at a point M. if angle R equal to 95 degree and Angle S equal to 31 degree find the measure of angle PMQ
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W.K.T , The sum of interior angles of quadrilateral is 360 degree, so we have;
∠P+∠Q+∠R+∠S = 360°
∠P+∠Q+100°+50° = 360°
∠P+∠Q = 360°−150°
∠P+∠Q = 210°......................(i)
Now, OP and OQ are the bisectors of angles P and Q respectively.
So, ∠P = 2∠OPQ and ∠Q = 2∠OQP
Equation (i) becomes
2∠OPQ+2∠OQP = 210°
2(∠OPQ+∠OQP) = 210°
∠OPQ+∠OQP = 105°..................(ii)
In triangle POQ,
∠POQ+∠OPQ+∠OQP = 180°
∠POQ+105° = 180° [Using(ii)]
∠POQ = 180°−105°
= 75°
Therefore, angle POQ is 75 degree.
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