the bisectors of the acute angles of a right triangle meet at O. find the angle at O between the two bisectors
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135 degree is the angle at O b/w the two bisectors
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Given: ABC is the right angle triangle, the right angle will be formed at B.
AO and OC are the angle bisectors of
∠BAC and ∠BCA
To Find That:
∠AOC
Solution:
Since AO and OC are the angle bisectors of ∠BAC and ∠BCA
∠OAC = 1/2 ∠BAC - (1)
∠OCA = 1/2 ∠BCA - (2)
Now we will add equation 1 and 2
∠OAC + ∠OCA = 1/2 ∠BAC + 1/2∠BCA
= 1/2(∠BAC + ∠BCA)
= 1/2 (180-∠ABC)
(the sum of interior angles is 180 degrees)
∠OAC + ∠OCA = 1/2 [180-90]
= 1/2 * 90
= 45
- (3)
Now in the triangle AOC,
∠AOC = 180 - [∠OAC + ∠OCA]
= 180 - 45
= 135
So the angle at O between the two bisectors is 135 Degrees.
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