The bisectors of the base angles of an isosceles triangle ABC, with AB=AC, meet at O. If ∠B = ∠C = 50°. What is the measure of angle O? also give the diagram
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Given:
In triangle ABC,
AB=AC meet at O
∠B = ∠C = 50°
measure of angle O=?
According to the question we make the diagram, and diagram are in the attachment
In ΔABC
∠OBC = ∠ OCB =25 (here OB and OC are bisectors)
By angle sum property in triangle OBC, we get
∠O + ∠ B + ∠ C = 180°
∠O + 25° + 25° =180
∠O + 50° = 180°
∠O = 180° - 50°
∠O = 130°
Hence measure of angle O is ∠O = 130°
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