Question

The bisects of exterior angles at B and C of triangle ABC meet at O. If angle A=x°, then angle BOC is

Answer 1

Answer:

In the given figure, bisects of exterior angles ∠Band ∠C meet at O and ∠A = x°

We need to find ext. ∠BOC

Now, according to the theorem, “if the sides AB and AC of a ΔABC are produced to P and Qrespectively and the bisectors of ∠PBC and ∠QCB intersect at O, therefore, we get,

∠BOC=90∘-12∠A

Hence, in ΔABC

∠BOC=90∘-12∠A

∠BOC=90∘-12x

Thus,