Math, asked by soniyalama449, 6 days ago

the bisertor AD of angle BAC of triangle ABC bisect as the side BD at D . prove that Triangle ABC is an isosceles triangle​

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Answered by animish02008
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Answer:

In ΔABC, let the altitude AD bisects ∠BAC

In ΔABC, let the altitude AD bisects ∠BACThen we have to prove that the ΔABC is isosceles.

In ΔABC, let the altitude AD bisects ∠BACThen we have to prove that the ΔABC is isosceles.In triangle ADB and ADC,

In ΔABC, let the altitude AD bisects ∠BACThen we have to prove that the ΔABC is isosceles.In triangle ADB and ADC,∠BAD=∠CAD (AD is bisector of ∠BAC)

In ΔABC, let the altitude AD bisects ∠BACThen we have to prove that the ΔABC is isosceles.In triangle ADB and ADC,∠BAD=∠CAD (AD is bisector of ∠BAC)AD=AD (common)

In ΔABC, let the altitude AD bisects ∠BACThen we have to prove that the ΔABC is isosceles.In triangle ADB and ADC,∠BAD=∠CAD (AD is bisector of ∠BAC)AD=AD (common)∠ADB=∠ADC (Each equal to 90

In ΔABC, let the altitude AD bisects ∠BACThen we have to prove that the ΔABC is isosceles.In triangle ADB and ADC,∠BAD=∠CAD (AD is bisector of ∠BAC)AD=AD (common)∠ADB=∠ADC (Each equal to 90 o

In ΔABC, let the altitude AD bisects ∠BACThen we have to prove that the ΔABC is isosceles.In triangle ADB and ADC,∠BAD=∠CAD (AD is bisector of ∠BAC)AD=AD (common)∠ADB=∠ADC (Each equal to 90 o )

In ΔABC, let the altitude AD bisects ∠BACThen we have to prove that the ΔABC is isosceles.In triangle ADB and ADC,∠BAD=∠CAD (AD is bisector of ∠BAC)AD=AD (common)∠ADB=∠ADC (Each equal to 90 o )⇒ΔADB≅ΔADC (by ASA congruence criterion)

In ΔABC, let the altitude AD bisects ∠BACThen we have to prove that the ΔABC is isosceles.In triangle ADB and ADC,∠BAD=∠CAD (AD is bisector of ∠BAC)AD=AD (common)∠ADB=∠ADC (Each equal to 90 o )⇒ΔADB≅ΔADC (by ASA congruence criterion)⇒AB=AC (cpct)

In ΔABC, let the altitude AD bisects ∠BACThen we have to prove that the ΔABC is isosceles.In triangle ADB and ADC,∠BAD=∠CAD (AD is bisector of ∠BAC)AD=AD (common)∠ADB=∠ADC (Each equal to 90 o )⇒ΔADB≅ΔADC (by ASA congruence criterion)⇒AB=AC (cpct)Hence, ΔABCis an isosceles.

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