Question

The BJT has IB=10 uA,Ico=1uA, what is collector current Ic ?

Answer 1

The complete question is:

A BJT has IB = 10 μA, α = .99 and ICBO = 1 μA. what is collector current Ic?

1.09 mA is the collector current(Ic).

Explanation:

Given that,

$I_{B}$ = 10 μA

α = .99

$I_{CBO}$ = 1 μA

To find,

$I_{C}$ = ?

Procedure:

As we know,

$I_{C}$ = β $I_{B}$  + ( 1 + β) $I_{CBO}$

Since we don't have β, we will find it

β = α/(1-α)

= .99/(1 - 0.99)

= 0.99/0.01

= 99

Now,

by putting the values in the formula $I_{C}$ = β $I_{B}$  + ( 1 + β) $I_{CBO}$

$I_{C}$ = 99 * 10 + (1 + 99) 1

$I_{C}$ = 990 + 100

∵ $I_{C}$ = 1090 μA

or

$I_{C}$ = 1.09 mA

Learn more: Collector current

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