Question

the blades of a windmill sweep out a circle of area A
(a) if the wind flows at a velocity v perpendicular to the circle. what is the mass of the air passing through a in time t?
(b) what is the kinetic energy of the air?
(c) assume that windmill converts 25% of the wind energy into electrical energy and that a equal 30m^2 , v= 36m^2 , v=36km/h and the density of air is 1.2kg/m^3. what is the electrical power produced

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Answer 1

Answer:

answer is getting below:-

Explanation:

• (a) Volume of wind flowing per sec = Av Mass of wind blowing per sec = Avρ Mass of air passing in time t = Avρt

• (b) K.E. of air = 1/2 mv2 = 1/2 (Avρt)v2 = 1/2 Av3ρt

• (c) Electrical energy produced = [25/100] x K.E. of air = 1/4 x 1/2 Av3ρt Electric power = w/t = 1/8 {Av3ρt}/{t} = 1/8 Av3ρ = 1/8 x 30 x (10)3 x 12 = 4500 watt = 4.5 kWRead more on Sarthaks.com - https://www.sarthaks.com/573157/the-blades-windmill-sweep-out-circle-area-the-wind-flows-velocity-perpendicular-the-circle