Question

The block of mass 3kg on a horizontal frictionless surface as shown in figure is being pulled by the light horizontal string at an acceleration 2m/s^(2) .What is the tension developed in the string? 1) 6N 2) 3N 3) 2N 4) 4N​

Answer 1

$\Large{\underline{\underline{\bf{Solution :}}}}$

★ Given :

Mass (m) = 3 kg

Acceleration (a) = 2m/s²

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★ To Find :

We have to find tge force.

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★ Solution :

$\Large{\implies{\boxed{\boxed{\sf{Force = Mass \times Acceleration}}}}}$

$\sf{→Force = 3 \times 2} \\ \\ \sf{→Force = 6 \: N} \\ \\ \Large{\implies{\boxed{\boxed{\sf{F = 6 \: N}}}}}$

Answer 2

$\large{\underline{\underline{\mathfrak{Answer :}}}}$

(1) Tension developed between string is 6N

$\rule{200}{0.5}$

$\underline{\underline{\mathfrak{Step-By-Step-Explanation :}}}$

Given :

• Mass of Block (m) = 3kg
• Acceleration (a) = 2 m/s²

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To Find :

• Tension developed in string (Force)

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Solution :

We know that :

$\large{\boxed{\sf{F \: = \: ma}}} \\ \\ \implies {\sf{F \: = \: 3 \: \times \: 2}} \\ \\ \implies {\sf{F \: = \: 6}} \\ \\ \underline{\sf{\therefore \: Tension \: developed \: in \: string \: is \: 6 \: N}}$

$\rule{200}{2}$

$\large\underline{\underline{\mathfrak{Additional \: Information \: :}}}$

• SI unit of force is N (kgm/s²).

• F = ma

• Force is a Vector quantity.

• Force is denoted by capital F.