Question

the block of mass M is placed on a horizontal surface. if the block is pulled by applying a force of magnitude F = 5 mg at an angle theta = 37 degree with the horizontal as shown in the figure find the acceleration of the block at the given instant​

Answer 1

The horizontal component of the force would produce the acceleration i.e. Fsin37.

Acc. = force/mass= mgsin37/m= g*3/5.

acc. =
$\frac{9.8 \times 3}{5}$
acc= 5.88 m/sq.s

Answer 2

hope it's clear............