Question

The block of mass M moving on the frictionless horizontal surface collides with the spring of spring constant k and compresses it by length L. The maximum momentum of the block after collision is [AIEEE 2005]​

Answer 1

Answer:

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Explanation:

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Answer 2

Explanation:- momentum would be maximum when KE would be maximum and this is the vade when total elastic PE is converted into KE

According to conservation of energy ,

⟹ 1/2KL² = 1/2Mv²

⟹ KL² = (MV)²/M

⟹ Or, MKL² = p² [∵ p = MV]

⟹ p = L√MK Answer this is the maximum momentum of block after collision .