Question

The blocks shown in figure (9-E19) have equal masses. The surface of A is smooth but that of B has a friction coefficient of 0.10 with the floor. Block A is moving at a speed of 10 m/s towards B which is kept at rest. Find the distance traveled by B if

(a) the collision is perfectly elastic and
(b) the collision is perfectly inelastic. Take g=10 m/s².

Answer 1

The elastic collision is 10 m/s and inelastic collision is 5 m/s.

Explanation:

V1 = 10 m/s  

V2 = 0

v1,v2→ velcity of A and B after collision a.

If the collision is perfectly elastic .

mV1+mV2 = Mv1 + mv2

→ 10 + 0 = v1 + v2

v1 + v2 = 10 ----(1)

Again v1+v2=−(u1−v2)

= − (10.0) = −10   ----(2)

Subtracting (2) from (1)

2v2 = 20

→ v2 = 10 m /s

The deceleration of B

→ h = 100 / 2 × 1 × 10 = 50 m

If the collision is perfectly inelastic

m × u1 + m × u2 = (m + m) × v

→ m × 10 + m × 0 = 2 m × v

→ v = (10 / 2) = 5 m / s

The two blocks will move together sticking to each other.

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