The bob A of a simple pendulum is released when
the string makes an angle of 45° with the vertical.
It hits another bob B of the same material and
same mass kept at rest on the table. If the collision is elastic
(a) Both A and B rise to the same height
(b) Both A and B come to rest at B
(c) Both A and B move with the same velocity of A
(d) A comes to rest and B moves with the velocity of A
Answers
Answered by
1
Answer:
Explanation:
As bob B is of same material and same mass as the bob A, therefore, on elastic collision, their velocities are exchanged.
Bob A comes to rest and B moves with the velocity of A.
We can prove this by momentum conservation and e=1.
e=
Speedofapproach
Speedofseparation
=
u
1
v
2
−v
1
=1
⇒v
2
−v
1
=u
1
−(I)
mu
1
=mv
1
+mv
2
⇒v
2
+v
1
=u
1
−(II)
Using(I)&(II)
v
1
=0&v
2
=u
1
Answered by
0
Answer:
d is the correct answer because in elastic collision if mass is same
Explanation:
so velocity of moving body is interchanged withbody which is in rest we can say v1=v2
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