The bob (mass m) of a simple pendulum of length L is held horizontal and then released. It collides inelastically with a block of equal mass lying on a
frictionless table. The speed of the block after collision will be -
i) zero
ii) √gL
iii) 2√gL
iv) √ gL/2
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Answer:
hey mate here is the answer
Explanation:
option 3 is correct answer 2 √gL
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