The bob of a pendulam of length 1.5 m is released from the position A shown in fig what is the speed with wch it reach B given that 5% of its initial energy is dissipated against air resistance
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Length of the pendulum, l = 1.5 m
Mass of the bob = m
Energy dissipated = 5%
According to the law of conservation of energy, the total energy of the system remains constant.
At the horizontal position:
Potential energy of the bob, EP = mgl
Kinetic energy of the bob, EK = 0
Total energy = mgl … (i)
At the lowermost point (mean position):
Potential energy of the bob, EP = 0
Kinetic energy of the bob, Ek = ½ mv²
Total energy. Ex = ½ mv² … (ii)
As the bob moves from the horizontal position to the lowermost point, 5% of its energy gets dissipated.
The total energy at the lowermost point is equal to 95% of the total energy at the horizontal point, i.e.,
(see the pic up)
Mass of the bob = m
Energy dissipated = 5%
According to the law of conservation of energy, the total energy of the system remains constant.
At the horizontal position:
Potential energy of the bob, EP = mgl
Kinetic energy of the bob, EK = 0
Total energy = mgl … (i)
At the lowermost point (mean position):
Potential energy of the bob, EP = 0
Kinetic energy of the bob, Ek = ½ mv²
Total energy. Ex = ½ mv² … (ii)
As the bob moves from the horizontal position to the lowermost point, 5% of its energy gets dissipated.
The total energy at the lowermost point is equal to 95% of the total energy at the horizontal point, i.e.,
(see the pic up)
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