Question

The Bob of a simple harmonic pendulum of mass 0.025kg is displaced 0.1m from its equilibrium position . if the angular frequency is 4rads^-1 and assuming simple harmonic motion , calculate the energy of the system ?

Answer 1

9.00m/sec  Will be the correct answer

Answer 2

Answer:

2.0 x 10^-3

Explanation:

force constant (k)=mass x angular velocity

k=0.025 x 16

k.=0.4kg/s²

kinetic energy=½kr²

K.E.=0.5 x0.4 x 0.1²

K.E.=2.0 x 10^-3