Question

The bob of a simple pendulum has mass 2g and a charge of 5.0 μC . It is at rest in a
uniform horizontal electric field of intensity 2000
V/m. At equilibrium, the angle that the
pendulum makes with the vertical is: (take g = 10
m/s² )
(A) tan⁻¹ (2.0)
(B) tan⁻¹ (0.2)
(C) tan⁻¹ (5.0)
(D) tan⁻¹ (0.5)

Answer 1

Answer:

sorry I don't know............

Answer 2

The value of "θ" the angle that the  pendulum makes with the vertical is

θ =  tan^-1 (0.5)

Option (d) is correct.

Explanation:

Given data:

• Mass f bob = 2 g
• Charge on bob = 5.0 μC
• Electric field intensity = 2000 V /m

tanθ =  qE  / mg

tanθ = 5 × 10^−6  × 2000 / 2 × 10^−3  × 10

tanθ = 1/2

θ =  tan^-1 (0.5)

Thus the value of "θ" the angle that the  pendulum makes with the vertical is

θ =  tan^-1 (0.5)

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