the bob of a simple pendulum is imparted a velocity 5 m\s when it at its mean position. to what maximum height will it rise on reaching to its extreme position of 60% of its energy is lost in overcoming friction of air. take g= 10 m\ S2
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⛦Hᴇʀᴇ Is Yoᴜʀ Aɴsᴡᴇʀ⚑
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➧ At the maximum height say ‘h’ the mechanical energy of the bob is only potential energy. So,
➾ PE = mgh
➧ But due to loss of energy in air resistance, only 40% of initial mechanical energy is converted to PE.
➾ PE = (40 / 100) K.E
➾ mgh = (0.4) (½ m) (5²)
➾ h = (0.4) (0.5) (25) (1 / 10)
➾ 0.5 m ...✔
_________
Thanks...✊
▬▬▬▬▬▬▬▬▬▬▬▬☟
➧ At the maximum height say ‘h’ the mechanical energy of the bob is only potential energy. So,
➾ PE = mgh
➧ But due to loss of energy in air resistance, only 40% of initial mechanical energy is converted to PE.
➾ PE = (40 / 100) K.E
➾ mgh = (0.4) (½ m) (5²)
➾ h = (0.4) (0.5) (25) (1 / 10)
➾ 0.5 m ...✔
_________
Thanks...✊
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