Question

The bob of a simple pendulum is imparted a velocity of 5 m / s when it is at its mean position. to what maximum vertical height will it rise on reaching at its extreme position if 60% Of its energy is lost in overcoming the friction of air.
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Answer 1

Answer:

When it is at mean position it will have a K.E  of  0.5mv2.

K.E=0.5×m×5×5=12.5×m J

60 % of this K.E is lost hence remaining  is equal to (40/100)12.5×m=5m

P.E=mgh=5×m

h=5/g=5/10=0.5m

Hence it goes to  a height of 0.5m.

Explanation:

PLS MARK AS BRAINLIEST

Answer 2

When it is at mean position it will have a K.E of 0.5mv 2 .K.E=0.5×m×5×5=12.5×m J60 % of this K.E is lost hence remaining is equal to (40/100)12.5×m=5mP.E=mgh=5×mh=5/g=5/10=0.5mHence it goes to a height of 0.5m.