Question

the Bob of a simple pendulum is imparted a velocity of 5m-¹ when it is at its mean position . to what maximum vertical height will it rise on reaching at its extreme position if 60% of its energy is lost in overcoming the friction of air

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Answer 1

When it is at mean position it will have a Kinetic Energy of 0.5mv².

$K.E= \: 0.5×m×5×5=12.5m \: J$

60 % of this K.E is lost hence remaining is equal to

$\frac{40}{100} \times 12.5m=5m$

Potential Energy = mgh = 5m

$h= \frac{5}{g} = \frac{5}{10} =0.5m$

Hence it goes to a height of 0.5m.

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