Question

The Bob of a simple pendulum of length l has a positive charge q on it. The pendulum is fixed to a horizontally oriented positively charged sheet. The time period of the small oscillations of simple pendulum is

Answer 1

Answer:

less than 2pi root (l/g)

Explanation:

In a normal case, acceleration on bob of pendulum is just g.

In this case, net acceleration = g + qE/m  

(qE=ma)

Hence T'= 2pi root (l/(g+qE/m))

Denominator increases, so time period decreases.