the bob of a simple pendulum released at point a hits another same mass of bobby at rest on the table assuming the collision as elastic how I will the pop of arise after collision and what will happen to bob of b
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As bob B is of same material and same mass as the bob A, therefore, on elastic collision, their velocities are exchanged.
Bob A comes to rest and B moves with the velocity of A.
We can prove this by momentum conservation and e=1.
e=
Speedofapproach
Speedofseparation
=
u
1
v
2
−v
1
=1
⇒v
2
−v
1
=u
1
−(I)
mu
1
=mv
1
+mv
2
⇒v
2
+v
1
=u
1
−(II)
Using(I)&(II)
v
1
=0&v
2
=u
1
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