The bob of simple pendulum having length l, is displaced from mean position to an angular position θ with respect to vertical. If it is released, then velocity of bob at lowest position :
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The bob of simple pendulum having length l, is displaced from mean position to an angular position θθ with respect to vertical. If it is released, then velocity of bob at lowest position :
( A ) 2gl−−−√2gl
( B ) 2gl(1−cosθ)−−−−−−−−−−−√2gl(1−cosθ)
( C ) 2glcosθ−−−−−−−√2glcosθ
( D ) 2gl(1+cosθ)−−−−−−−−−−−√
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Answer:
Explanation- take h=l-lcos
Acceleration = g
Then put it in equation v^2=u^2 +2as
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