The bob of simple pendulum is held in the horizantal position calculate the speed of the bob of pendulum at the lowest position B when released and the length of pendulum is 0.5 meter and assume that there is no loss of energy
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Answer:
Increase in potential Energy of bob
=
m
g
Δ
h
where
m
is mass of bob,
g
=
9.81
m
s
−
2
is acceleration due to gravity and
Δ
h
is change in height of bob.
As shown in the figure,
Δ
h
=
L
−
L
cos
θ
. Inserting given values we get
Work done on the bob
=
0.5
×
9.81
(
20
−
20
cos
30
∘
)
⇒
Work done on the bob
=
0.5
×
9.81
×
20
(
1
−
√
3
2
)
=
13.1
J
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