the bob of simple pendulum of length 1m has mass 100g and speed 1.4 m/s at lowest point . find tension in string at this moment
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At lowest point, two forces are acting on the bob
a) Tension in string upwards
b) mg downwards.
As it is moving along circular path hence
T−mg=mv2rT−mg=mv2r
=> T=mg+mv2rT=mg+mv2r
Given mm = 100g = 0.1 Kg, vv= 1.4 m/s, rr= ll= 1 m, g=10m/s2g=10m/s2
Hence T = 1.196 N
Hope you are satisfied.....
a) Tension in string upwards
b) mg downwards.
As it is moving along circular path hence
T−mg=mv2rT−mg=mv2r
=> T=mg+mv2rT=mg+mv2r
Given mm = 100g = 0.1 Kg, vv= 1.4 m/s, rr= ll= 1 m, g=10m/s2g=10m/s2
Hence T = 1.196 N
Hope you are satisfied.....
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