Question

The body centered cubic element of density 10.5
has a cell edge of 409pm. Calculate its atomic mass .

​

Answer 1

Answer:

Density-d= a

3

×NA

Z×M

​Given :

Molar Mass(M)=108g/mol

Density (d)=10.5g/cm

3

Edge Length(a)=409pm

Z=

M

d×a

3

×N

Value of N

A

​

 is N

A

​

=6.023×10

23

Z= 108

10.5×(409×10 −10cm 3 ) 3×6.023×10

23 =4

Number of atoms =4