The body falling with the speed of 2 m/s strikes the floor and rebounds with the speed of 1 m/s. the loss of energy is
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If m is the mass of body then,
Initial energy = 0.5mu^2 = 0.5 * m * (2)^2 = 2m
Final energy = 0.5mv^2 = 0.5 * m * 1^2 = 0.5m
Loss in energy = 2m - 0.5m = 1.5m
Percentage loss in energy
= 1.5m/(2m) * 100 = 75%
Initial energy = 0.5mu^2 = 0.5 * m * (2)^2 = 2m
Final energy = 0.5mv^2 = 0.5 * m * 1^2 = 0.5m
Loss in energy = 2m - 0.5m = 1.5m
Percentage loss in energy
= 1.5m/(2m) * 100 = 75%
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1
Answer:
The answer is 75%.
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