Question

The body is thrown vertically u the greatest height h to which it will rise is

Answer 1

Answer:

u²/2g

Explanation:

Here, motion is opposite to the gravity, so, acceleration on -ve of g → a = - g

At the highest point, its velocity becomes 0.

Using equations of motion:

v² = u² + 2aS

=> 0 = u² + 2(-g)H

=> - u² = - 2gH

=> u² = 2gH

=> u²/2g = H

Answer 2

Explanation:

at ground body will have kinetic Energy =

1÷2 × mv^2

At maximum hight Potential Energy = mgh

mgh = 1÷2 × mv^2 (Conservation of energy)

h = v^2 ÷ (2g)