the body of weight 10 Newton is suspended by a string 100 mm long and is held at a point 60 mm from the vertical line passing through the point of suspension by a horizontal force. The horizontal force is?
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Answer:
As the mass is at rest the resultant of forces acting on it are equal to zero
so forces in vertical direction are
T
1
sin30
o
+T
2
sin60
o
−mg=0
2
T
1
+
2
3
T
2
=5g
T
1
+
3
T
2
=100
similarly in horizontal direction
T
1
cos30
o
−T
2
cos60
o
=0
T
2
T
1
=
3
1
solving above equations will give us
T
1
+
3
×
3
T
1
=100
T
1
=25N
T
2
=25
3
N
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