Physics, asked by sanjanaanjana2108, 9 months ago

the body started falling freely from the point above the ground it's velocity after 2 seconds will be​

Answers

Answered by rishikkarthik
0

Answer:

19.6 m/s

Explanation:

We know that Acceleration of any object falling towards is 9.8m/s^2 ,Given U = 0( freely falling),T = 2sec ,V=?

W.k.T A=V-U/T

9.8 = V-0/2

V=9.8×2 = 19.6 m/s

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Answered by amitnrw
0

19.6 m/s² will be velocity after 2 seconds  if the body started falling freely  

Explanation:

We  know that

V = U + at

U = initial Velocity

a = acceleration

V = Final Velocity

T = time duration

U = 0    as body started falling freely

a = g  = 9.8 m/s²

t = 2 sec

V = ?

=> V = 0  + 9.8 * 2

=> V = 19.6  m/s

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