Question

the Bohr orbit radius for the hydrogen atom (n=1) is approximately 0.530 armstrom. The radius for the excited state (n=2) will be

Answer 1

a=n^2 /z × 0.530 A°

So therefore 2^2× 0.530 =4×0.53 = 2.12 A°

Answer 2

Answer:

So therefore 2^2× 0.530 =4×0.53 = 2.12 A°