Question

the boiling point of a solution of 0.11g of substance in 15g of ether was found to be 0.1 degree higher than that of pure ether the molecular weight of the substance will be (Kb=2.16KKgmol)

Answer 1

Answer: 158.4 g/mol

Explanation: Formula used for Elevation in boiling point :

$\Delta T_b=k_b\times m$

or,

$T_{solvent}-T_{solution}=k_b\times \frac{\text{mass of solute}}{\text{molar mass of solute}\times \text{weight of solvent in kg}}$

where,

$T_b$ = change in boiling point

$k_b$ = boiling point constant  = 2.16 K/kgmol

m = molality

$T_{solvent}-T_{solution}=2.16\times \frac{0.11g}{M\times 0.015kg}$

$0.1=2.16\times \frac{0.11g}{M\times 0.015kg}$

$M=158.4g/mol$

Answer 2

Answer:

Explanation:

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