Chemistry, asked by shalommusic71, 9 months ago

The boiling point of an aqueous solution of 0.2m Al2(SO4)3 is (kb=0.52) ( assuming 100% dissociation) ​

Answers

Answered by puspendrakannaujiya4
1

Explanation:

1000 g solvent + 22.5 g NaI • 100 = 2.2 % NaI ... The molality of the solution is (2.4 mol C3H5(OH)3, 0.425 kg H2O)= 5.7 m. 9. ... and the boiling point will be 61.70 + 0.808 = 62.51 ˚C ...

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