Question

The boiling point of an aqueous solution of a non volatile solute is 100.15°c .What is freezing point of an aqueous solution obtained by diluting the above solution with an equal volume of water ? The values of Kb and Kf of water are 0.512 and 1.86 K molality-1

Answer 1

The boiling point of an aqueous solution of a non volatile solute is 100.15°c .What is freezing point of an aqueous solution obtained by diluting the above solution with an equal volume of water and the values of Kb and Kf of water are 0.512 and 1.86 K molality-1.

Then it follows that;

For boiling point,

Tb = i x kb x M

100.15 + 273 = 1 x 0.512 x M

M = 728. 80

Then let us calculate M after adding 500 ml water

M x V = M' x 2V

M' = M/2

728.8/2

M' =364.4

Then Tf = 1 x kf x M'

          Tf = 1 x 1.86 x 364.4

           Tf = 677.8 K

Answer 2

Answer:

Explanation

Answer given below