Question

The Boiling Point of Benzene is 353.23 K. When 1.80 Gram of Non-volatile Solute Was Dissolved in 90 Gram of Benzene, the Boiling Point is Raised to 354.11 K. Calculate the Molar Mass of Solute.
Derive an Expression for Maximum Work in Isothermal Reversible Expansion of Two Moles of an Ideal Gas.

Answer 1

Given,

Weight of solute = 1.80g

Weight of solvent = 90 g

Kb for benzene = 2.53 K kg/ mole

Suppose Molar weight of solute = x g

Boiling point elevation = 354.11  K - 353.23K = 0.88 K

Tb =Kb * M  

M= 1.80*1000/x*90

0.88 = 1.80*1000/x*90

x = 1.80*1000/0.88*90

on solving this u will get the ans.