Question

the boiling point of chlorine is -34°C. Solve for temperature in degree Fahrenheit and Kelvin Scale​

Answer 1

Celsius to Fahrenheit :-

$\bf \dag F = \dfrac{9}{5} ^{ \circ} C+ 32$

$: \implies \sf \dfrac{9}{5} \times - 34 + 32$

$: \implies \sf - 61.2 + 32$

$: \implies \bf - 29.2 ^{ \circ} F$

Celsius to Kelvin :-

$\bf \dag K= \ ^{ \circ} C+273$

$: \implies \sf -34+273$

$: \implies \bf 239K$

Answer 2

Answer:

Given :-

• The boiling point of chlorine is - 34°C.

To Find :-

• What is the temperature in degree fahrenheit and kelvin scale.

Solution :-

$\sf\bold{\underline{\bold{\purple{\bigstar\: In\: case\: of\: degree\: fahrenheit\: scale\: :-}}}}$

As we know that :

$\longrightarrow \sf\boxed{\bold{\pink{^{\circ}F =\: \bigg(\dfrac{9}{5} \times\: ^{\circ}C\bigg) + 32}}}$

Given :

• °C = - 34

According to the question by using the formula we get,

$\leadsto \bf ^{\circ}F =\: \bigg(\dfrac{9}{5} \times\: ^{\circ}C\bigg) + 32$

$\leadsto \bf ^{\circ}F =\: \dfrac{9}{5} \times (- 34) + 32$

$\leadsto \sf ^{\circ}F =\: \dfrac{- 306}{5} + 32$

$\leadsto \sf ^{\circ}F =\: - 61.2 + 32$

$\leadsto \sf\bold{\red{^{\circ}F =\: - 29.2^{\circ}}}$

$\therefore$ The temperature in degree fahrenheit scale is 29.2°F .

$\sf\bold{\underline{\bold{\purple{\bigstar\: In\: case\: of\: degree\: kelvin\: scale\: :-}}}}$

As we know that :

$\dashrightarrow \sf\boxed{\bold{\pink{^{\circ}K =\: ^{\circ}C + 273}}}$

Given :

• °C = - 34

According to the question by using the formula we get,

$\mapsto \bf ^{\circ}K =\: ^{\circ}C + 273$

$\mapsto \sf ^{\circ}K =\: - 34 + 273$

$\mapsto \sf\bold{\red{^{\circ}K =\: 239}}$

$\therefore$ The temperature in degree kelvin scale is 239K .