Question

the boiling point of solution containing 6.62g of substance A in 100g of water is higher by 0.0512°C then the boiling point of pure water, the molar mass of substance is?

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Answer 1

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Answer 2

Given info : the boiling point of solution containing 6.62g of substance A in 100g of water is higher by 0.0512°C then The boiling point of pure water.

To find : the molar mass of substance is ..

solution : change in boiling point, ∆Tb = 0.0512°C

mass of water (solvent) = 100g

mass of substance A (solute) = 6.62 g

we know, ∆Tb = Kb × m

for water, ebulioscopic constant, Kb = 0.512 k kg/mol

∴ 0.0512 = 0.512 × m

⇒ m = 0.1

m is molality so m = no of moles of substance A/mass of solvent in kg

⇒0.1 = (6.62/M)/(100/1000)

⇒0.1 = 66.2/M

⇒M = 662 g/mol

Therefore the molar mass of substance A is 662 g