Question

the boiling point of water on the top of mount everest is 70 C while at murree 98 C Explain this difference​

Answer 1

Hi,

If we go by the definition of boiling point, it is the temp. when the vapor pressure of the liquid is equal to the atmospheric pressure.

Now, thats too much physics so leave it there for some time and see excatly what happens.

At any given temp. liquid state water molecule has tendency to escape the water surface. The force between each molecules of water binds them, however few break it and fly off(which we know as evaporation and it happens at all temp in liquid state of water however is directly proportional to temp.). Also, the atmospheric pressure on the surface of water press it and restrain from breaking that bond between molecules of water and leaving the water surface.

As we go high and high, the atmospheric pressure decrease, hence the pressing force weakens. As the heat is provided to water, with less amount of heat absorbed by its molecules it can break the mutual bond and fly off the surface of water, since the pressing force is weakened due to decrease pressure.

So, at sea level and at Everest, water is same and mutual force of bonding between the molecules is same, and we provide the same amount of heat. However, the the pressing force decrease (atmospheric pressure decrease) with less amount of heat absorbed water molecules are able to break the bond and leave the surface.

This means that if you go further high, the water will boil at 50 degree C.

Coming to definition now, the vapour pressure is the amount of water molecule just above the water surface and atmospheric pressure is the pressure exerted by the atmosphere on the water surface. When these to equals up, the water starts leaving the surface vigorously which we see as boiling.

This is true for all the liquids.

hope this helps you...Plzz Mark as brainliest answer...