Question

the Boling point of benzene is 353.23k. when 1.80 gram of non -volatile solute was dissolved in 90g benzene the boiling point is raised to 354.11k . calculate the molar mass of solute given kb for benzene is 2.53 KgMol^-1​

Answer 1

Answer:

ans is 0.5016

∆Tb=KbWeight of solute /Mx weight of solvent)

∆Tb= boiling point of solution - boiling point of pure solvent

= 354.11-253.23=100.88

kb= 5.12

weight of solute = 1.8 g

weight of solvent = 90x10^-3 kg

molar mass = M

now using above formula solve the problem.

agar solve karne me koi problem ho to

uper photo mein dekho