Chemistry, asked by loneayash5289, 1 year ago

The bond length of hcl bond is 2.29 x 10-10 m. The percentage ionic character of hcl, if measured dipole moment is 6.226 x 10-30cm, is

Answers

Answered by abhi178
9

bond length of HCl, l = 2.29 × 10^-10m

magnitude of charge on H^+ or Cl^- , q =1.6 × 10^-19C

so theoretically, dipole moment of HCl = ql

= 1.6 × 10^-19C × 2.29 × 10^-10m

= 3.664 × 10^-29 Cm

we know,

% ionic character of HCl = experimental dipole moment /theoretical dipole moment × 100

= 6.226 × 10^-30/3.664 × 10^-29 × 100

=0.1699 × 100

= 16.99% ≈ 17%

hence, percentage ionic character of HCl is 17%

Answered by jaswasri2006
0
  • The experimental value of the dipole moment of HCl is 1.03 D. The length of H – Cl bond is 1.275 Å. The percentage of ionic character of HCl is closer to 17% .
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